Umhlaba kunye ne-ertyisi

Cinga ngomhlaba (njengengqukuva ene \(r_1 = 6370km\) ) kunye neertyisi (njengengqukuva ene \(r_2 = 2mm\) ) kwaye wolule intambo ukunqumla i-ikhweyitha ukuze ilale ngokuqinileyo phezu komhlaba. Ngoku yandisa zombini iintambo ngemitha enye. Zombini iintambo ngoku kufuneka zilale zolule ngokupheleleyo ngaphezu kwe-ikhweyitha - kodwa azisekho ngokupheleleyo kumphezulu, kodwa zidada ngaphezu kwe-ikhweyitha. Ingaba intambo idada phezu komhlaba, iphakame kangakanani phezu kweertyisi?


Iintambo ezimbini ekuqaleni zinobude:

$$
l_1 = 2\cdot 6370 km \cdot \pi \Leftrightarrow r_1 = 6370 km = \frac{l_1}{2 \cdot \pi}
$$

njenge

$$
l_2 = 2 \cdot 2mm \cdot \pi \Leftrightarrow r_2 = 2mm = \frac{l_2}{2 \cdot \pi}.
$$

Kodwa ngoku kusemva kolwandiso

$$
r_{1 NEU} = \frac{l_1 + 1m}{2\cdot \pi}
$$

njenge

$$
r_{2 NEU} = \frac{l_2 + 1m}{2\cdot \pi}.
$$

Kodwa ngoku kuyamangalisa

$$
r_{1 NEU} - r_1 = \frac{l_1 + 1m}{2\cdot \pi} - \frac{l_1}{2\cdot \pi} = \frac{l_1 + 1m - l_1}{2 \cdot \pi} = \frac{1m}{2 \cdot \pi} = 0.159m
$$

njenge

$$
r_{2 NEU} - r_2 = \frac{l_2 + 1m}{2\cdot \pi} - \frac{l_2}{2\cdot \pi} = \frac{l_2 + 1m - l_2}{2 \cdot \pi} = \frac{1m}{2 \cdot \pi} = 0.159m.
$$

Yiyo loo nto umgama ukusuka kumphezulu uzimele nge \(l_1\) okanye \(l_2\) , \(l_2\) uzimele kwi radii \(r_1\) okanye \(r_2\) yamacandelo. Impendulo emangazayo yile: Zombini ezi ntambo \(0.159m\) ngobude obufanayo \(0.159m\) ) ngaphezulu komphezulu womhlaba.

Emva