\(r_1 = 6370km\) dhulka (sida kubbadda leh \(r_1 = 6370km\) ) iyo digir (sida kubbadda leh \(r_2 = 2mm\) ) kuna \(r_2 = 2mm\) xarig dusha sare si ay si adag dusha dushiisa ugu jiifto. Hadda waxaad ku dheereyneysaa labada xadhig midkiiba hal mitir. Labada xadhigba waa inay hadda si buuxda ugu ballaadhiyaan dhulbaraha mar labaad - mar dambe si buuxda dusha ugama jiifinayaan, laakiin waxay ku dul sababayaan dhulgariirka. Intee ka sarreeyaa dusha sare ee xariggu uu ku dul saboobaa dhulka korkiisa, intee ka sarreeyaa digirta?
Labada xadhig waxay leeyihiin dhererka koowaad:
$$
l_1 = 2\cdot 6370 km \cdot \pi \Leftrightarrow r_1 = 6370 km = \frac{l_1}{2 \cdot \pi}
$$
sida
$$
l_2 = 2 \cdot 2mm \cdot \pi \Leftrightarrow r_2 = 2mm = \frac{l_2}{2 \cdot \pi}.
$$
Laakiin hadda waa kordhinta kadib
$$
r_{1 NEU} = \frac{l_1 + 1m}{2\cdot \pi}
$$
sida
$$
r_{2 NEU} = \frac{l_2 + 1m}{2\cdot \pi}.
$$
Laakiin hadda waa wax la yaab leh
$$
r_{1 NEU} - r_1 = \frac{l_1 + 1m}{2\cdot \pi} - \frac{l_1}{2\cdot \pi} = \frac{l_1 + 1m - l_1}{2 \cdot \pi} = \frac{1m}{2 \cdot \pi} = 0.159m
$$
sida
$$
r_{2 NEU} - r_2 = \frac{l_2 + 1m}{2\cdot \pi} - \frac{l_2}{2\cdot \pi} = \frac{l_2 + 1m - l_2}{2 \cdot \pi} = \frac{1m}{2 \cdot \pi} = 0.159m.
$$
Marka masaafada dusha sare ka madax banaan \(l_1\) ama \(l_2\) , \(l_2\) madax banaan raadiye \(r_1\) ama \(r_2\) qaybaha. Jawaabta yaabka leh ayaa ah sidan: Labada \(0.159m\) isla dhererka \(0.159m\) ) dusha sare.