Xisaabta Corona

Warbixinta toddobaadlaha ah ee RKI ee 11.11.2021 waxay ku taxan tahay bogga 22 in \(36\%\) bukaannada ka weyn 60-jirka ee ku jira qaybta daryeelka degdegga ah ay si buuxda u tallaaleen. Kooxdan da'da ah, \(87\%\) si buuxda loo tallaalay waqtigan (eeg bogga 18).


Waxaa laga yaabaa in:

  • \(G\): Dadka da'doodu ka weyn tahay 60 sano waa la tallaalaa
  • \(U\): Dadka ka weyn 60 sano lama tallaalo
  • \(I\): Dadka da'doodu ka weyn tahay 60 sano ayaa ku jira daryeelka degdegga ah

Hadda waa

$$P(G) = 0,87 \wedge P(U) = 0,13.$$

Sidoo kale waa

$$P(G|I) = \frac{P(G \cap I)}{P(I)} = 0,36 \wedge P(U|I) = \frac{P(U \cap I)}{P(I)} = 0,64.$$

Waa sidaas oo kale

$$P(G \cap I) = 0,36 \cdot P(I) \wedge P(U \cap I) = 0,64 \cdot P(I)$$

iyo sababta

$$P(I|U) = \frac{P(I \cap U)}{P(U)} = \frac{P(U \cap I)}{P(U)} = \frac{0,64 \cdot P(I)}{0,13} \Rightarrow P(I) = \frac{0,13 \cdot P(I|U)}{0,64}.$$

Way daba socotaa

$$P(I|G) = \frac{P(I \cap G)}{P(G)} = \frac{P(G \cap I)}{P(G)} = \frac{0,36 \cdot P(I)}{0,87} = \frac{0,36 \cdot \frac{0,13 \cdot P(I|U)}{0,64}}{0,87} = \frac{0,36 \cdot 0,13}{0,64 \cdot 0,87} \cdot P(I|U) \approx 0,08 \cdot P(I|U).$$

Taas macnaheedu waxa weeye in khatarta dadka ka weyn 60 sano ee ku dambayn doonta daryeelka degdegga ah ee fayraska Korona ay ka badan tahay 10 jeer dadka aan la tallaalin marka loo eego kuwa la tallaalay.

Dib u laabo