Duo considerare \(A\) et \(B\) qui eodem die nati \(A\) minor \(B\) . Monstra: Sunt duo annos prorsus constellations \(a,b \in \mathbb{N}\) : Quae est: \(2\cdot a = b\) . Nos prius set \(d \in \mathbb{R}^+\) ut aetatis differentia inter \(A\) et \(B\) in partu autem \(A\) et \( d = d_0 + d_1 \) , \( d_0 \in \mathbb{N}_0, d_1 \in \mathbb{R}, d_1 \in [0;1[\) . Nos Nunc considero punctum tempore \(x \in \mathbb{R}^+\) Post cujus ortum \(A\) et \(x = x_0 + x_1\) : \(x_0 \in \mathbb{N}_0, x_1 \in \mathbb{R}, x_1 \in [0;1[\) .
At iam hoc tempore per definitionem: \(a = \lfloor x \rfloor \) et \(b = \lfloor x+d \rfloor\) . Nunc definiri \(x\) quam habet:
$$2 \lfloor x \rfloor = \lfloor x+d \rfloor \Leftrightarrow 2 \lfloor x_0 + x_1 \rfloor = \lfloor x_0 + x_1 + d_0 + d_1 \rfloor$$
1 si: \(0 \leq x_1 + d_1 < 1\):
Et $$2 \lfloor x_0 + x_1 \rfloor = \lfloor x_0 + d_0 + \underbrace{x_1 + d_1}_{< 1} \rfloor \Leftrightarrow 2 x_0 = x_0 + d_0 \Leftrightarrow x_0 = d_0.$$
Et hoc modo, quod $$a = \lfloor x \rfloor = \lfloor x_0 + x_1 \rfloor = \lfloor d_0 + x_1 \rfloor = d_0$$ et $$b = \lfloor x + d \rfloor = \lfloor x_0 + x_1 + d_0 + d_1 \rfloor = \lfloor 2 d_0 + \underbrace{x_1 + d_1}_{< 1} \rfloor = 2 d_0$$ prima aetate $$b = \lfloor x + d \rfloor = \lfloor x_0 + x_1 + d_0 + d_1 \rfloor = \lfloor 2 d_0 + \underbrace{x_1 + d_1}_{< 1} \rfloor = 2 d_0$$ pro.
2 si: \( 1 \leq x_1 + d_1 < 2 \):
Et $$2 \lfloor x_0 + x_1 \rfloor = \lfloor x_0 + d_0 + \underbrace{x_1 + d_1}_{\geq 1} \rfloor \Leftrightarrow 2 x_0 = x_0 + d_0 + 1 \Leftrightarrow x_0 = d_0 + 1.$$
Et hoc modo, quod $$a = \lfloor x \rfloor = \lfloor x_0 + x_1 \rfloor = \lfloor d_0 + 1 + x_1 \rfloor = d_0 + 1$$ et $$b = \lfloor x+d \rfloor = \lfloor x_0 + x_1 + d_0 + d_1 \rfloor = \lfloor 2 d_0 + 1 + \underbrace{x_1 + d_1}_{\geq 1} \rfloor = 2 d_0 + 2$$ ad alterum constellatio desideravit aetatem.
Nominatim hisce Litteris modo, exempli gratia, si tua mater peperit vobis ante annos \(20\) annis, est prorsus in tempore vestra bis \(40\) et \(42\) annis. Etiam interesting, et, si quod est \(n\) tempora, quia vetera: Ecce \(n \in \mathbb{N}\) ad arbitrium suum, et ut \(x_0 = \frac{d_0}{n-1} \in \mathbb{N} \Leftrightarrow d_0 = k (n-1)\) . Hoc operatur prorsus cum aetate integri difference \( \lfloor d \rfloor = d_0 \) aeque multiplices, \(n-1\) : mater tua est, si exempli causa superius per \(24\) anno \(6\) temporis aetas tua.